Why Centering and Scaling Features Matters in Data Preprocessing
Introduction
When working with datasets in machine learning and data science, one of the most important preprocessing steps is standardization. Datasets are often represented as a matrix XXX, where rows correspond to observations (or samples) and columns correspond to features (or variables). Different features can have very different ranges of values. For example, one feature might represent “age” measured in years, ranging from 0 to 100, while another feature might represent “income” in thousands, ranging from 10 to 1000. If left untreated, these differences in scale can affect algorithms like gradient descent, k-means clustering, or principal component analysis, since features with larger magnitudes may dominate the learning process. To avoid this imbalance, we standardize each feature so that it has zero mean and unit variance.

The process of standardizing a dataset involves centering and scaling each feature. Mathematically, the transformation for each feature xjx_jxj in the dataset is: xj′=xj−μjσjx’_j = \frac{x_j – \mu_j}{\sigma_j}xj′=σjxj−μj
Here:
- xjx_jxj is the original feature value,
- μj\mu_jμj is the mean of feature jjj,
- σj\sigma_jσj is the standard deviation of feature jjj,
- xj′x’_jxj′ is the standardized feature value.
This transformation ensures that:
- The mean of each feature becomes 0.
- The variance (and hence standard deviation) of each feature becomes 1.
Now, considering the matrix XXX, which has dimensions (n×d)(n \times d)(n×d), where nnn is the number of samples and ddd is the number of features:
- First, compute the mean vector μ\muμ of size 1×d1 \times d1×d.
- Subtract this mean vector from every row of XXX. This centers the data, so each feature column has mean zero.
- Next, compute the standard deviation vector σ\sigmaσ of size 1×d1 \times d1×d.
- Divide each feature column by its standard deviation. This scales the data so that variance becomes one.
In matrix terms, the standardized version of XXX, denoted as X′X’X′, can be written as: X′=X−μσX’ = \frac{X – \mu}{\sigma}X′=σX−μ
where subtraction and division are applied column-wise.

It is important to note that multiplying XXX by its transpose (i.e., computing XXTX X^TXXT) is not standardization. Instead, this operation produces a Gram matrix, which represents the pairwise dot products between rows of XXX. While such a matrix is useful in kernels and similarity calculations, it does not normalize the data. Standardization requires shifting and rescaling feature values directly, not forming cross-product matrices.
Therefore, the correct procedure for achieving zero mean and unit variance is to transform the dataset column-wise using the feature-wise mean and standard deviation, not simply multiplying XXX by its transpose.

Conclusion
In conclusion, standardization of matrix XXX is a vital preprocessing step that ensures fair contribution of each feature in machine learning algorithms. The process involves subtracting the mean and dividing by the standard deviation for each column of the dataset, thereby transforming features to have zero mean and unit variance. This makes algorithms more stable, speeds up convergence in optimization, and improves interpretability of results. While operations like XXTX X^TXXT are useful in other contexts such as similarity measurement or dimensionality reduction, they do not achieve standardization. Thus, for effective machine learning preprocessing, one must carefully apply the correct transformation: feature-wise centering and scaling.